Given a linked list, remove the n-th node from the end of list and return its head.
Example:
Given linked list: 1->2->3->4->5, and n = 2. After removing the second node from the end, the linked list becomes 1->2->3->5. Solution 1:
public class Solution {
public ListNode removeNthFromEnd(ListNode head, int n) {
if(head == null) return null;
int count = 0;
ListNode temp = head;
ListNode returnNode = head;
ListNode before = null;
while(temp!=null){
temp = temp.next;
count++;
}
for(int i = 0;head!=null && i<count-n;i++){
before = head;
head = head.next;
}
if(returnNode == head){
head = head.next;
returnNode = head;
}else{
before.next = head.next;
}
return returnNode;
}
}
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